50 poin nih,copas gpp tp jan ngawur
Jawaban:
penyelesaian
ditanya :
tentukan nilai x dan y ......?
jawab
[tex] \frac{x}{x + 2} = \frac{6}{10} \\ 10x = 6x + 12 \\ 4x = 12 \\ x = \frac{12}{4} \\ x = 3 \\ \\ \frac{y}{10} = \frac{6}{10} \\ y = \frac{10 \times 6}{10} \\ y = 6[/tex]
semoga membantu
Jawaban:
Answer+Explain:
Diketahui:
- BC = 10 cm
- AD = 6 cm
- DB = 4 cm
- AB = 4 cm + 6 cm = 10 cm
- EC = 2 cm
Penyelesaian:
a.) mencari nilai x
[tex]\frac{AD}{AE} = \frac{DB}{EC} \\ \\ \frac{6}{x} = \frac{4}{2} \\ \\ x = \frac{6 \times 2}{4} \\ \\ x = \frac{12}{4} \\ x = 3 \: cm[/tex]
b.) mencari nilai y
[tex]\frac{ED}{CB} = \frac{AD}{AB} \\ \\ \frac{y}{10} = \frac{6}{10} \\ \\ y = \frac{6 \times 10}{10} \\ y = 6 \: cm[/tex]
note:
- dalam operasinya menggunakan perkalian silang
semoga membantu :)